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Proof step 8 from proof int2bytes-fillsgn-rec (previous step)

# int2bytes(i >> 8) < n, i < ~128 ∨ 128 ≤ i ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = fillsgn(n - 1, int2bytes(i >> 8)) + i2b(i) '

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 9:
⊦ # bytes ≥ n → fillsgn(n, bytes) = bytes
Proof step 10:
¬ # int2bytes(i >> 8) ≥ n - 1, # int2bytes(i >> 8) < n, i < ~128 ∨ 128 ≤ i ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = fillsgn(n - 1, int2bytes(i >> 8)) + i2b(i) '
Proof step 38:
# int2bytes(i >> 8) ≥ n - 1, # int2bytes(i >> 8) < n, i < ~128 ∨ 128 ≤ i ⊦ fillsgn(n, int2bytes(i >> 8) + i2b(i) ') = int2bytes(i >> 8) + i2b(i) '

Rule argument

name: fillsgn-longer rotate: F subst: [bytes, n] → [int2bytes(i >> 8), n - 1]

Additional information

Used terms: int2bytes(i >> 8), n - 1