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Proof step 2 from proof int2bytes-first-neg-01 (previous step)

int2bytes(i) = i2b(0) ' + bytes, i < 0, i2b(0) ∈ int2bytes(i) ⊦

User applied rule induction

And obtained the following new goals

Proof step 3:
int2bytes(i) = i2b(0) ' + bytes ∧ i < 0 ∧ i2b(0) ∈ int2bytes(i), ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + bytes ∧ i0 < 0 ∧ i2b(0) ∈ int2bytes(i0) → false ⊦ false

Rule argument

indvar: i→n(i) wfpred: <

Additional information

Used simplifier rules: <; (wellfounded) Used terms: i→n(i)