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Proof step 6 from proof int2bytes-first-neg (previous step)

int2bytes(i) = by ' + bytes, i < 0, 0 ≤ b2i(by), by ∈ int2bytes(i), ∀ bytes, by, i0. i→n(i0) < i→n(i) → int2bytes(i0) = by ' + bytes ∧ by ∈ int2bytes(i0) ∧ 0 ≤ b2i(by) ∧ i0 < 0 → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
⊦ i < ~ 128 → int2bytes(i) = int2bytes((i - 255) / 256) + int2bytes(i % 256).last '
Proof step 8:
¬ i < ~ 128, int2bytes(i) = by ' + bytes, i < 0, 0 ≤ b2i(by), by ∈ int2bytes(i), ∀ bytes, by, i0. i→n(i0) < i→n(i) → int2bytes(i0) = by ' + bytes ∧ by ∈ int2bytes(i0) ∧ 0 ≤ b2i(by) ∧ i0 < 0 → false ⊦
Proof step 14:
i < ~ 128, int2bytes((i - 255) / 256) + int2bytes(i % 256).last ' = by ' + bytes, i < 0, 0 ≤ b2i(by), by ∈ int2bytes((i - 255) / 256) + int2bytes(i % 256).last ', ∀ bytes, by, i0. i→n(i0) < i→n(i) → int2bytes(i0) = by ' + bytes ∧ by ∈ int2bytes(i0) ∧ 0 ≤ b2i(by) ∧ i0 < 0 → false ⊦

Rule argument

name: int2bytes-rec255-neg rotate: F subst: [i] → [i]

Additional information

Used terms: i