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Proof step 10 from proof int2bytes-first-zerobyte-01 (previous step)

8 * 0 > i0 * 8 + j0, n→i(# int2bits(j)) = i0 * 8 + j0, i0 < 0, 0 ≤ j0, 0 ≤ j, j0 < 8 ⊦ j0 = 1 ↔ (∃ i. ¬ i < 0 ∧ ¬ j < 2 ^ (8 * i - 1) ∧ ¬ 2 ^ (8 * i) ≤ j)

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 2 flags: rotate, discard

Additional information

Used simplifier rules: ⊦ i > j ↔ j < i;% ⊦ ¬ n→i(n) < 0;