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Proof step 17 from proof int2bytes-first-zerobyte-01 (previous step)

0 ≤ i0 ∧ 0 ≤ 8, # int2bits(j) = i→n(i0) * i→n(8) + i→n(j0), j0 < 8, 0 ≤ j, 0 ≤ j0, 0 ≤ i0 ⊦ j0 = 1 ↔ (∃ i. ¬ i < 0 ∧ ¬ j < 2 ^ (8 * i - 1) ∧ ¬ 2 ^ (8 * i) ≤ j)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 18:
# int2bits(j) = i→n(j0) + 8 * i→n(i0), j0 < 8, 0 ≤ j, 0 ≤ j0, 0 ≤ i0 ⊦ j0 = 1 ↔ (∃ i. ¬ i < 0 ∧ ¬ j < 2 ^ (8 * i - 1) ∧ ¬ 2 ^ (8 * i) ≤ j)

Proof step 17 from proof int2bytes-first-zerobyte-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

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