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Proof step 27 from proof int2bytes-first-zerobyte-01 (previous step)

1 = i→n(j0) + 8 * i→n(i0), 0 ≤ i0, 0 ≤ j0, j0 < 8 ⊦ 0 * 8 + 1 = i→n(i0) * 8 + i→n(j0), 0 = i→n(i0) ∧ 1 = i→n(j0), j0 = 1 ↔ (∃ i. ¬ i < 0 ∧ ¬ 0 < i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 28:
⊦ m * 0 = 0
Proof step 29:
1 = i→n(j0) + 8 * i→n(i0), 0 ≤ i0, 0 ≤ j0, j0 < 8 ⊦ 0 + 1 = i→n(i0) * 8 + i→n(j0), 0 = i→n(i0) ∧ 1 = i→n(j0), j0 = 1 ↔ (∃ i. ¬ i < 0 ∧ ¬ 0 < i)

Rule argument

seq: ⊦ m * 0 = 0 subst: [m] → [8] rotate: F spec: nat-mult inst: name: ax-03

Additional information

Used simplifier rules: ⊦ m * n = n * m; Used terms: 8