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Proof step 49 from proof int2bytes-first-zerobyte-01 (previous step)

j < 2 ^ (8 * i0), 2 ^ (8 * i0 - 1) ≤ j, 0 ≤ j, 0 < i0 ⊦ i0 = 0, 8 * i→n(i0) = 1, ∃ i. ¬ i < 0 ∧ ¬ j < 2 ^ (8 * i - 1) ∧ ¬ 2 ^ (8 * i) ≤ j

Heuristic quantifier closing applied rule exists right

And closed the goal!

Rule argument

pos: right 3 terms: i0

Additional information

Used simplifier rules: ⊦ i < j → ¬ j < i;% ⊦ i * j = j * i;% ⊦ i ≤ j → (¬ ¬ j < i ↔ false);% ⊦ i < j → (¬ ¬ j ≤ i ↔ false); Used terms: i0