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Proof step 15 from proof int2bytes-first-zerobyte (previous step)

i ≤ 127, 0 ≤ i, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → (int2bytes(i0).first = i2b(0) ↔ n→i(# int2bits(i0)) % 8 = 1) ⊦ i2b(i) = i2b(0) ↔ n→i(# int2bits(i)) % 8 = 1

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i = 0

Additional information

Used simplifier rules: ⊦ int2bits(0) = false ';% ⊦ # boolvar ' = 0 +1; Used formulas: i = 0