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Proof step 6 from proof int2bytes-first-zerobyte (previous step)

0 ≤ i, i ≤ 255, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → (int2bytes(i0).first = i2b(0) ↔ n→i(# int2bits(i0)) % 8 = 1) ⊦ int2bytes(i).first = i2b(0) ↔ n→i(# int2bits(i)) % 8 = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 7:
0 ≤ i, i ≤ 127 ⊦ int2bytes(i) = i2b(i) '
Proof step 8:
¬(0 ≤ i ∧ i ≤ 127), 0 ≤ i, i ≤ 255, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → (int2bytes(i0).first = i2b(0) ↔ n→i(# int2bits(i0)) % 8 = 1) ⊦ int2bytes(i).first = i2b(0) ↔ n→i(# int2bits(i)) % 8 = 1
Proof step 14:
0 ≤ i ∧ i ≤ 127, 0 ≤ i, i ≤ 255, ∀ i0. i→n(i0) < i→n(i) → 0 ≤ i0 → (int2bytes(i0).first = i2b(0) ↔ n→i(# int2bits(i0)) % 8 = 1) ⊦ i2b(i) '.first = i2b(0) ↔ n→i(# int2bits(i)) % 8 = 1

Rule argument

name: int2bytes-le127 rotate: F subst: [i] → [i]

Additional information

Used terms: i