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Proof step 2 from proof int2bytes-index-rightshift-01 (previous step)

n < # int2bytes(i) ⊦ int2bytes(i)[n] = i2b(i >> 8 * (n→i(# int2bytes(i)) - n→i(n) + 1))

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 ≤ j ∧ j < n→i(# int2bytes(i)) → int2bytes(i)[i→n(j)] = i2b(i >> 8 * (n→i(# int2bytes(i)) - j + 1))

Rule argument

name: int2bytes-index-rightshift subst: [j, i] → [n→i(n), i]

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ 0 ≤ n→i(n);% ⊦ n→i(m) < n→i(n) ↔ m < n;% ⊦ ¬ m < n ↔ n ≤ m;% ⊦ m < n → (n ≤ m ↔ false);% ⊦ i→n(n→i(n)) = n; Used terms: n→i(n), i