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Proof step 12 from proof int2bytes-index-rightshift-02 (previous step)

¬(0 ≤ # int2bytes(i) - i→n(i1) ∧ # int2bytes(i) - i→n(i1) < # int2bytes(i)), 0 ≤ i1, i1 ≤ n→i(# int2bytes(i)), i1 ≤ 4, 0 < i1 ⊦ int2bytes(i)[# int2bytes(i) - i→n(i1)] = i2b(i >> 8 * (i1 - 1))

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ m < n ↔ n ≤ m;% ⊦ 0 ≤ m;