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Proof step 5 from proof int2bytes-index-rightshift-02 (previous step)

0 ≤ i1, i1 ≤ n→i(# int2bytes(i)), i1 ≤ 4, 0 < i1 ⊦ int2bytes(i)[# int2bytes(i) - i→n(i1)] = i2b(i i>> 8 * (i1 - 1))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 6:
⊦ j i>> i = j >> band(i, 31)
Proof step 7:
0 ≤ i1, i1 ≤ n→i(# int2bytes(i)), i1 ≤ 4, 0 < i1 ⊦ int2bytes(i)[# int2bytes(i) - i→n(i1)] = i2b(i >> band(8 * (i1 - 1), 31))

Rule argument

seq: ⊦ j i>> i = j >> band(i, 31) subst: [i, j] → [8 * (i1 - 1), i] rotate: F spec: intops inst: name: intshiftright-def-unbounded

Additional information

Used terms: 8 * (i1 - 1), i