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Proof step 18 from proof int2bytes-index-rightshift (previous step)

j < n→i(# int2bytes(i)), 0 ≤ j, i→n(n→i(# int2bytes(i)) - j + 1) < # int2bytes(i) ⊦ int2bytes(i)[i→n(j)] = firstn(# int2bytes(i) - i→n(n→i(# int2bytes(i)) - j + 1), int2bytes(i)).last

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

seq: ⊦ m ≠ 0 ∧ m ≤ # bytes → firstn(m, bytes).last = bytes[m -1] subst: [bytes, m] → [int2bytes(i), # int2bytes(i) - i→n(n→i(# int2bytes(i)) - j + 1)] rotate: F spec: list-del inst: bytelist name: firstn-last

Additional information

Used simplifier rules: ⊦ n < m → m - n ≠ 0;% ⊦ m < n → ¬ n < m;% ⊦ ¬ m ≤ n ↔ n < m;%n0 ≤ n ⊦ n - n0 ≤ m ↔ n ≤ m + n0;% ⊦ ¬ m + n < m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: int2bytes(i), # int2bytes(i) - i→n(n→i(# int2bytes(i)) - j + 1)