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Proof step 27 from proof int2bytes-last-01 (previous step)

~256 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i, ~256 = i ∨ ~128 ≤ i ⊦ int2bytes(i % 256).last = i2b(i)

User applied rule cut formula

And obtained the following new goals

Proof step 28:
~256 = i, ~256 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i, ~256 = i ∨ ~128 ≤ i ⊦ int2bytes(i % 256).last = i2b(i)
Proof step 31:
~256 ≤ i, i < 128 ∨ 256 ≤ i, i < ~128 ∨ 128 ≤ i, ~256 = i ∨ ~128 ≤ i ⊦ ~256 = i, int2bytes(i % 256).last = i2b(i)

Rule argument

fma: ~256 = i

Additional information

Used formulas: ~256 = i