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Proof step 38 from proof int2bytes-last-01 (previous step)

i % 256 ≤ 255, 0 < i % 256, 127 < i % 256, 0 ≤ i, 0 < i, 256 ≤ i ⊦ ~256 = i, i2b(i % 256 - 256) = i2b(i)

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 39:
⊦ i2b(i + 256) = i2b(i)
Proof step 40:
i % 256 ≤ 255, 0 < i % 256, 127 < i % 256, 0 ≤ i, 0 < i, 256 ≤ i ⊦ ~256 = i, i2b((i % 256 - 256) + 256) = i2b(i)

Rule argument

seq: ⊦ i2b(i + 256) = i2b(i) subst: [i] → [i % 256 - 256] rotate: T spec: byte inst: name: byte-add-256

Additional information

Used terms: i % 256 - 256