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Proof step 1 from proof int2bytes-le255 (conclusion)

127 < i, i ≤ 255 ⊦ int2bytes(i) = i2b(0) ' + i2b(i - 256) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
127 < i, i ≤ 255, 0 < i, 0 ≤ i ⊦ bits2bytes(int2bits(i)) = i2b(0) ' + i2b(i - 256) '

Rule argument

Additional information

Used simplifier rules: int2bytes: ⊦ int2bytes(i) = bits2bytes(int2bits(i));% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ (* i) < j ∧ 0 < i → 0 ≤ j ∧ 0 < j; (forward)