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Proof step 10 from proof int2bytes-le255 (previous step)

8 < # int2bits(i), 127 < i, i ≤ 255, 0 < i, 0 ≤ i ⊦ bits2bytes(firstn(# int2bits(i) - 8, int2bits(i))) + i2b(bits2int(lastn(8, int2bits(i)))) = i2b(0) ' + i2b(i - 256) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ int2bits(j) ≠ [];% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)% ⊦ bytes + by = bytes + by ';