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Proof step 13 from proof int2bytes-le255 (previous step)

0 ≤ i, 0 ≤ i, 0 < i, i ≤ 255, 127 < i, 8 < # uint2bits(i) ⊦ bits2bytes(firstn(# uint2bits(i) - 8, uint2bits(i))) + i2b(bits2int(lastn(8, uint2bits(i)))) ' = i2b(0) ' + i2b(i - 256) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: 0 ≤ i ⊦ uint2bits(i) ≠ [];% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i < j → ¬ j < i;% ⊦ # bits = 0 ↔ bits = [];% ⊦ m < n → n ≠ 0; (forward)