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Proof step 4 from proof int2bytes-le255 (previous step)

¬ 8 < # int2bits(i), 127 < i, i ≤ 255, 0 < i, 0 ≤ i ⊦ bits2bytes(int2bits(i)) = i2b(0) ' + i2b(i - 256) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
127 < i, i ≤ 255, 0 < i, 0 ≤ i, # int2bits(i) ≤ 8 ⊦ i2b(i) ' = i2b(0) ' + i2b(i - 256) '

Rule argument

Additional information

Used simplifier rules: bits2bytes-base: ⊦ # bits ≤ 8 → bits2bytes(bits) = i2b(bits2int(bits)) ';% ⊦ bits2int(int2bits(i)) = i;% ⊦ ¬ m < n ↔ n ≤ m;