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Proof step 7 from proof int2bytes-le255 (previous step)

0 ≤ i, 127 < i, i ≤ 255, 0 < i, 0 ≤ i, # uint2bits(i) ≤ 8 ⊦ i2b(i) ' = i2b(0) ' + i2b(i - 256) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information