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Proof step 13 from proof int2bytes-leading-zeros (previous step)

¬(127 < i ∧ i ≤ 255), int2bytes(i) = i2b(0) ' + i2b(0) ' + bytes, 0 ≤ i, i ≤ 255, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 14:
int2bytes(i) = i2b(0) ' + i2b(0) ' + bytes, 0 ≤ i, i ≤ 127, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

Rule argument

Additional information

Used simplifier rules: j0 ≠ 0, j ≤ j0 ⊦ i ≤ (* j) → i ≤ (* j0);% ⊦ ¬ i < j ↔ j ≤ i;