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Proof step 35 from proof int2bytes-leading-zeros (previous step)

int2bytes(i % 256) = bytes0 + i2b(0) ', int2bytes(i / 256) = i2b(0) ', 255 < i, 0 ≤ i, 0 < i, i2b(0) ∈ int2bytes(i % 256), ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Rule argument

name: int2bytes-rec-pos rotate: F subst: [i] → [i / 256]

Additional information

Used simplifier rules: int2bytes-empty: ⊦ int2bytes(i) ≠ [];% ⊦ 0 ≤ i ∧ 0 < j ∧ 0 < j0 → (i / j) / j0 = i / (j * j0);% ⊦ by ' = bytes + by0 ' ↔ by = by0 ∧ bytes = [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; Used terms: i / 256