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Proof step 38 from proof int2bytes-leading-zeros (previous step)

int2bytes(i / 256) = i2b(0) ', int2bytes(i % 256) = bytes0 + i2b(0) ', i / 256 ≤ 255, i2b(0) ∈ int2bytes(i % 256), 0 < i, 0 ≤ i, 255 < i, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 39:
127 < i, i ≤ 255 ⊦ int2bytes(i) = i2b(0) ' + i2b(i - 256) '
Proof step 40:
¬(127 < i / 256 ∧ i / 256 ≤ 255), int2bytes(i / 256) = i2b(0) ', int2bytes(i % 256) = bytes0 + i2b(0) ', i / 256 ≤ 255, i2b(0) ∈ int2bytes(i % 256), 0 < i, 0 ≤ i, 255 < i, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

Rule argument

name: int2bytes-le255 rotate: F subst: [i] → [i / 256]

Additional information

Used simplifier rules: ⊦ by ' = by0 ' + bytes ↔ by = by0 ∧ bytes = [];% ⊦ by ' ≠ [];% ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1; Used terms: i / 256