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Proof step 44 from proof int2bytes-leading-zeros (previous step)

int2bytes(i % 256) = bytes0 + i2b(0) ', i2b(i / 256) = i2b(0), i2b(0) ∈ int2bytes(i % 256), 0 < i, 0 ≤ i, 255 < i, i / 256 ≤ 127, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 45:
⊦ i2b(i) = i2b(j) ↔ b2i(i2b(i)) = b2i(i2b(j))
Proof step 46:
int2bytes(i % 256) = bytes0 + i2b(0) ', b2i(i2b(i / 256)) = b2i(i2b(0)), i2b(0) ∈ int2bytes(i % 256), 0 < i, 0 ≤ i, 255 < i, i / 256 ≤ 127, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦

Rule argument

seq: ⊦ i2b(i) = i2b(j) ↔ b2i(i2b(i)) = b2i(i2b(j)) subst: [j, i] → [0, i / 256] rotate: F spec: byte inst: name: i2b-equal

Additional information

Used terms: 0, i / 256