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Proof step 5 from proof int2bytes-leading-zeros (previous step)

int2bytes(i) = i2b(0) ' + i2b(0) ' + bytes ⊦ i < 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
int2bytes(i) = i2b(0) ' + i2b(0) ' + bytes, 0 ≤ i ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ ¬ i < j ↔ j ≤ i;