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Proof step 51 from proof int2bytes-leading-zeros (previous step)

bytes = bytes0 + by ', int2bytes(i / 256) = i2b(0) ' + i2b(0) ' + bytes0, int2bytes(i % 256).last = by, 0 < i, 0 ≤ i, 255 < i, ∀ bytes, i0. i→n(i0) < i→n(i) → int2bytes(i0) = i2b(0) ' + i2b(0) ' + bytes ∧ 0 ≤ i0 → false ⊦ bytes = []

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ (bytes + bytes0) + bytes1 = bytes + bytes0 + bytes1;% ⊦ bytes + by ' ≠ [];