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Proof step 19 from proof int2bytes-len-def (previous step)

m * 8 = m -1 * 8 + 8, # int2bits(i) = m * 8 ⊦ m = 0, m = 1 + (m * 8 - 1) / 8

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ n -1 = n - 1;% ⊦ n ≤ m → m + n0 - n = (m - n) + n0;% ⊦ (m + n0) + n1 = m + n0 + n1;%n ≠ 0 ⊦ (n0 + m * n) / n = n0 / n + m;% ⊦ 0 + m = m;% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n = n * m;% ⊦ m < 1 ↔ m = 0;% ⊦ ¬ m ≤ n ↔ n < m;%n ≤ m ⊦ (m - n) + n0 = n1 ↔ m + n0 = n + n1;