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Proof step 7 from proof int2bytes-len-def (previous step)

# int2bits(i) % 8 ≠ 0 ⊦ # int2bits(i) % 8 = 0, # int2bits(i) / 8 + 1 = 1 + (# int2bits(i) - 1) / 8

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
⊦ # int2bits(i) % 8 = 0, # int2bits(i) / 8 = (# int2bits(i) - 1) / 8

Rule argument

Additional information

Used simplifier rules: ⊦ m + n = n + m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = m + n0 ↔ n = n0;