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Proof step 1 from proof int2bytes-len-le-neg-02 (conclusion)

⊦ i < 0 ∧ int2bytes(i).first ≠ i2b(~1) → (# int2bytes(i) ≤ n ↔ ~(2 ^ (8 * n→i(n))) ≤ i)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
i < 0 ⊦ int2bytes(i).first = i2b(~1), # int2bytes(i) ≤ n ↔ ¬ 2 ^ (8 * n→i(n)) + i < 0

Rule argument

Additional information

Used simplifier rules: ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ~ i ≤ j ↔ 0 ≤ i + j;