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Proof step 16 from proof int2bytes-len-le (previous step)

¬ i < 2 ^ ((n→i(n) - 1) * 8), 0 ≤ i, 2 ^ (8 * n→i(# int2bytes(i) - 1)) ≤ i ⊦ n ≤ # int2bytes(i), int2bytes(i).first = i2b(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 17:
2 ^ ((n→i(n) - 1) * 8) ≤ i, # int2bytes(i) < n, 2 ^ (8 * n→i(# int2bytes(i) - 1)) ≤ i, 0 ≤ i ⊦ int2bytes(i).first = i2b(0)

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0;% ⊦ m < n → n ≠ 0; (forward)% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ ¬ m ≤ n ↔ n < m;