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Proof step 19 from proof int2bytes-len-le (previous step)

0 < b2i(int2bytes(i).first) → bytes2int(int2bytes(i).first ' + int2bytes(i).rest) < 2 ^ ((n→i(# int2bytes(i).rest) + 1) * 8 - 1), 2 ^ ((n→i(n) - 1) * 8) ≤ i, # int2bytes(i) < n, 2 ^ (8 * n→i(# int2bytes(i) - 1)) ≤ i, 0 ≤ i ⊦ int2bytes(i).first = i2b(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 20:
2 ^ ((n→i(n) - 1) * 8) ≤ i, # int2bytes(i) < n, 2 ^ (8 * n→i(# int2bytes(i) - 1)) ≤ i, 0 ≤ i, ¬ b2i(int2bytes(i).first) ≤ 0 → bytes2int(int2bytes(i).first ' + int2bytes(i).rest) < 2 ^ ((n→i(# int2bytes(i).rest) + 1) * 8 - 1) ⊦ int2bytes(i).first = i2b(0)

Rule argument

Additional information

Used simplifier rules: ⊦ ¬ i < j ↔ j ≤ i;