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Proof step 2 from proof int2bytes-len-le (previous step)

0 ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

User applied rule insert lemma

And obtained the following new goals

Proof step 3:
⊦ 0 < b2i(by) → 2 ^ (n→i(# bytes) * 8) ≤ bytes2int(by ' + bytes)
Proof step 4:
0 < b2i(int2bytes(i).first) → 2 ^ (n→i(# int2bytes(i).rest) * 8) ≤ bytes2int(int2bytes(i).first ' + int2bytes(i).rest), 0 ≤ i ⊦ int2bytes(i).first = i2b(0), n ≤ # int2bytes(i) ↔ ¬ i < 2 ^ ((n→i(n) - 1) * 8)

Rule argument

name: bytes2int-size-03 subst: [by, bytes] → [int2bytes(i).first, int2bytes(i).rest]

Additional information

Used terms: int2bytes(i).first, int2bytes(i).rest