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Proof step 21 from proof int2bytes-len-le (previous step)

2 ^ ((n→i(n) - 1) * 8) ≤ i, # int2bytes(i) < n, 2 ^ (8 * n→i(# int2bytes(i) - 1)) ≤ i, 0 ≤ i ⊦ ¬ b2i(int2bytes(i).first) ≤ 0, int2bytes(i).first = i2b(0)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 22:
b2i(int2bytes(i).first) ≤ 0, 0 ≤ i, 2 ^ (8 * n→i(# int2bytes(i) - 1)) ≤ i, # int2bytes(i) < n, 2 ^ ((n→i(n) - 1) * 8) ≤ i ⊦ int2bytes(i).first = i2b(0)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;% ⊦ j ≤ i ∧ i ≤ 0 → j ≤ 0; (forward)% ⊦ j ≤ j0 ∧ j0 ≤ j1 → j ≤ j1; (forward)