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Proof step 16 from proof int2bytes-len-ls-01 (previous step)

n→i(# int2bits(i)) = i0 * 8 + j ∧ 0 ≤ j ∧ j < 8 ∧ 0 ≤ i0 ∧ 0 < 8 ∧ 0 ≤ n→i(# int2bits(i)), j = 1, 0 < i ⊦ # int2bits(i) % 8 = 0, i = 0, n ≤ # int2bits(i) / 8 ↔ ¬ i < 2 ^ (n→i(n) * 8 - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ 0 ≤ n→i(n);