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Proof step 2 from proof int2bytes-len-ls-01 (previous step)

int2bytes(i).first = i2b(0), 0 ≤ i ⊦ n < # int2bytes(i) ↔ ¬ i < 2 ^ (n→i(n) * 8 - 1)

User applied rule cut formula

And obtained the following new goals

Rule argument

fma: i = 0

Additional information

Used simplifier rules: int2bytes-byte: ~128 ≤ i, i < 128 ⊦ int2bytes((* i)) = i2b(i) ';% ⊦ by '.first = by;%~128 ≤ i, i ≤ 127, ~128 ≤ j, j ≤ 127 ⊦ i2b((* i)) = i2b((* j)) ↔ i = j;% ⊦ # by ' = 0 +1;% ⊦ m < 1 ↔ m = 0;% ⊦ 0 < 2 ^ i ↔ 0 ≤ i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ 1 ≤ i ↔ 0 < i;% ⊦ 0 < i → (0 < i * j ↔ 0 < j);%0 ≤ i ⊦ (* i) < n→i(n) ↔ i→n(i) < n;% ⊦ 0 < n ↔ n ≠ 0;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i * j = j * i; Used formulas: i = 0