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Proof step 25 from proof int2bytes-len-ls-01 (previous step)

0 ≤ i0 ∧ 0 ≤ 8, # int2bits(i) = 1 + i→n(i0) * i→n(8), 0 < i, 0 ≤ i0 ⊦ # int2bits(i) % 8 = 0, i = 0, n ≤ # int2bits(i) / 8 ↔ ¬ i < 2 ^ (n→i(n) * 8 - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 26:
# int2bits(i) = 1 + 8 * i→n(i0), 0 < i, 0 ≤ i0 ⊦ # int2bits(i) % 8 = 0, i = 0, n ≤ # int2bits(i) / 8 ↔ ¬ i < 2 ^ (n→i(n) * 8 - 1)

Proof step 25 from proof int2bytes-len-ls-01 (previous step)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information