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Proof step 8 from proof int2bytes-len-ls-01 (previous step)

0 ≤ i, n→i(# int2bits(i)) % 8 = 1, 0 < i ⊦ i = 0, i = 0, n < # int2bytes(i) ↔ ¬ i < 2 ^ (n→i(n) * 8 - 1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 9:
n→i(# int2bits(i)) % 8 = 1, 0 < i ⊦ i = 0, n < # int2bytes(i) ↔ ¬ i < 2 ^ (n→i(n) * 8 - 1)

Rule argument

Additional information

Used simplifier rules: ⊦ i ≠ j → (i ≤ j ↔ i < j);