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Proof step 5 from proof int2bytes-len-ls (previous step)

¬ # int2bytes(i) ≤ n ↔ 2 ^ (8 * n→i(n)) ≤ i, 0 ≤ i ⊦ int2bytes(i).first = i2b(0), n < # int2bytes(i) ↔ ¬ i < 2 ^ (n→i(n) * 8)

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 2

Additional information

Used simplifier rules: ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ m < n → (n ≤ m ↔ false);% ⊦ i * j = j * i;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ ¬ m ≤ n ↔ n < m;