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Proof step 21 from proof int2bytes-len-neg-01 (previous step)

i + 2 < n→i(n0), 0 ≤ i, 0 < j + 2 ^ (8 * (i + 1)), j + 2 ^ (8 * (i + 1) - 1) < 0, j + 2 ^ (n→i(n0) * 8 - 2) < 0, 0 ≤ 2 ^ (n→i(n0) * 8 - 1) + j, j < 0 ⊦ n0 = 0, n0 * 8 = 1, n0 = 2 + i→n(i)

User applied rule cut formula

And obtained the following new goals

Proof step 22:
j + 2 ^ (8 * (i + 1)) < j + 2 ^ (8 * ((n→i(n0) - 2) + 1)), i + 2 < n→i(n0), 0 ≤ i, 0 < j + 2 ^ (8 * (i + 1)), j + 2 ^ (8 * (i + 1) - 1) < 0, j + 2 ^ (n→i(n0) * 8 - 2) < 0, 0 ≤ 2 ^ (n→i(n0) * 8 - 1) + j, j < 0 ⊦ n0 = 0, n0 * 8 = 1, n0 = 2 + i→n(i)

Rule argument

fma: j + 2 ^ (8 * (i + 1)) < j + 2 ^ (8 * ((n→i(n0) - 2) + 1))

Additional information

Used simplifier rules: ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ i + (j - i0) = i + j - i0;% ⊦ (* i) + i0 - (* j) = (i - j) + i0;%i < 0 ⊦ (* i) + j = j - ~ i;% ⊦ i + j < i + i0 ↔ j < i0;% ⊦ i * j * j0 = (i * j) * j0;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;% ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);%0 ≤ j ⊦ 2 ^ j < 2 ^ j0 ↔ j < j0;% ⊦ 0 < i → (i * j < i * j0 ↔ j < j0);% ⊦ i < j - i0 ↔ i + i0 < j;% ⊦ i + j < i0 ∧ ¬ j < j0 → i + j0 < i0; Used formulas: j + 2 ^ (8 * (i + 1)) < j + 2 ^ (8 * ((n→i(n0) - 2) + 1))