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Proof step 37 from proof int2bytes-len-neg-01 (previous step)

0 ≤ i + 2, n0 ≤ i→n(i + 2), i + 1 < n→i(n0), j < 0, 0 ≤ 2 ^ (n→i(n0) * 8 - 1) + j, j + 2 ^ (n→i(n0) * 8 - 2) < 0, j + 2 ^ (8 * (i + 1) - 1) < 0, 0 < j + 2 ^ (8 * (i + 1)), 0 ≤ i ⊦ n0 = 2 + i→n(i), n0 * 8 = 1, n0 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 38:
n0 ≤ i→n(i + 2), i + 1 < n→i(n0), j < 0, 0 ≤ 2 ^ (n→i(n0) * 8 - 1) + j, j + 2 ^ (n→i(n0) * 8 - 2) < 0, j + 2 ^ (8 * (i + 1) - 1) < 0, 0 < j + 2 ^ (8 * (i + 1)), 0 ≤ i ⊦ n0 = 2 + i→n(i), n0 * 8 = 1, n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;%i0 ≠ 0, i0 ≤ i ⊦ (* i) ≤ j → (* i0) ≤ j;% ⊦ (* j) ≤ i0 + (* j0) ↔ j - j0 ≤ i0;