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Proof step 48 from proof int2bytes-len-neg-01 (previous step)

# int2bits(j) = m * 8 + n ∧ n < 8 ∧ 8 ≠ 0, j < 0, j + 2 ^ (8 * (i + 1) - 1) < 0, # int2bits(j) ≤ i→n(8 * (i + 1)) + 1, 0 ≤ i ⊦ j + 2 ^ (8 * (i + 1)) = 0, m + 1 = i→n(i + 2), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 49:
# int2bits(j) = m * 8 + n, 0 ≤ i, m * 8 + n ≤ i→n(8 * (i + 1)) + 1, j + 2 ^ (8 * (i + 1) - 1) < 0, j < 0, n < 8 ⊦ n = 0, m + 1 = i→n(i + 2), j + 2 ^ (8 * (i + 1)) = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (forward)