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Proof step 60 from proof int2bytes-len-neg-01 (previous step)

¬ 0 ≤ n→i(m) * 8 + n→i(n) - 2, 0 ≤ i, 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 2 ^ (n→i(m) * 8 + n→i(n) - 1), j + 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 0, 0 ≤ 2 ^ (n→i(m) * 8 + n→i(n) - 1) + j, 8 * (i + 1) < n→i(m) * 8 + n→i(n), n < 8, j < 0, j + 2 ^ (8 * (i + 1) - 1) < 0, m * 8 + n ≤ 9 + 8 * i→n(i) ⊦ m * 8 + n = 0, j + 2 ^ (8 * (i + 1)) = 0, m + 1 = i→n(i + 2), n = 0, m = 0 ∧ n = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ 0 < n ↔ n ≠ 0;%0 ≤ i ⊦ (* i) < n→i(n) ↔ i→n(i) < n;% ⊦ i < 0 ∧ 0 ≤ j → i < j;% ⊦ i + j < i + i0 ↔ j < i0;% ⊦ i < j ∧ 0 ≤ i → 0 < j; (forward)% ⊦ i ≤ j ∧ 0 ≤ i → 0 ≤ j; (forward)% ⊦ j < i ∧ i ≤ 0 → j < 0; (forward)% ⊦ i < j ∧ j ≤ j0 → i < j0; (forward)% ⊦ 0 ≤ n→i(n);% ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);% ⊦ 2 ^ (i - 1) < 2 ^ i ↔ 0 ≤ i;%i < 0 ⊦ (* i) + j = j - ~ i;% ⊦ i + 0 = i;% ⊦ (* i) + i0 - (* j) = (i - j) + i0;% ⊦ i + 1 ≤ j ↔ i < j;% ⊦ 0 < i → (i * j ≤ i * i0 ↔ j ≤ i0);% ⊦ i < j + 1 ↔ i ≤ j;% ⊦ m0 * m * n = (m0 * m) * n;% ⊦ m * n ≤ m1 * n + n ↔ ¬ ¬(m ≤ m1 + 1 ∨ n = 0);%n < n0 ⊦ m + (* n) ≤ m0 + (* n0) ↔ m ≤ m0 + (n0 - n);% ⊦ i * j * j0 = (i * j) * j0;% ⊦ n→i(n) < 1 ↔ n = 0;% ⊦ 0 < i ∧ 0 ≤ j → ((* i) * i0 < (* j) ↔ i0 < (i + j - 1) / i);% ⊦ i + (* j) < (* j0) ↔ i < j0 - j;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + 1 ≠ 0;% ⊦ ¬ i ≤ j ↔ j < i;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ m + n = n + m;% ⊦ m * n = n * m;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ i + j = j + i;% ⊦ i * j = j * i;