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Proof step 64 from proof int2bytes-len-neg-01 (previous step)

0 ≤ i, j + 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 0, 0 ≤ 2 ^ (n→i(m) * 8 + n→i(n) - 1) + j, 8 * (i + 1) < n→i(m) * 8 + n→i(n), n < 8, j < 0, j + 2 ^ (8 * (i + 1) - 1) < 0, m * 8 + n ≤ 9 + 8 * i→n(i), 2 ≤ n→i(m) * 8 + n→i(n), 0 < n→i(m) * 8 + n→i(n), 0 ≤ n→i(m) * 8 + n→i(n) ⊦ m * 8 + n = 0, j + 2 ^ (8 * (i + 1)) = 0, m + 1 = i→n(i + 2), n = 0, m = 0 ∧ n = 1

User applied rule insert spec-lemma

And obtained the following new goals

Rule argument

seq: j * i + j0 < j * i0 + j1, 0 ≤ j0, j0 < j, abs(j1) < j ⊦ i ≤ i0 subst: [j, i, j0, i0, j1] → [8, i + 1, 0, n→i(m), n→i(n)] rotate: F spec: int-mult inst: name: modlsp-03

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i * j = j * i;% ⊦ i + j + i0 = (i + j) + i0;% ⊦ m * n = n * m;% ⊦ m + n = n + m;% ⊦ i + 0 = i;% ⊦ ¬ i < j ↔ j ≤ i;% ⊦ i < j → (¬ ¬ j ≤ i ↔ false);% ⊦ abs(n→i(n)) = n→i(n);%0 ≤ i ⊦ n→i(n) < (* i) ↔ n < i→n(i);% ⊦ ¬ m < n ↔ n ≤ m;% ⊦ m < n → (n ≤ m ↔ false); Used terms: 8, i + 1, 0, n→i(m), n→i(n)