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Proof step 15 from proof int2bytes-len-neg (previous step)

8 ≠ 0, n = n0, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), 0 ≤ i, 0 ≤ 2 ^ (8 * (i + 1) - 1) + j, j + 2 ^ (8 * i) ≤ 0, n→i(n0) ≤ i + 1, j + 2 ^ (n→i(n0) * 8 - 2) < 0, 0 ≤ 2 ^ (n→i(n0) * 8 - 1) + j, j < 0, 2 ^ (8 * i) ≤ 2 ^ (n→i(n0) * 8 - 1) ⊦ n0 = 0, n0 * 8 = 1, n0 = i→n(i) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 16:
2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), 0 ≤ i, 0 ≤ 2 ^ (8 * (i + 1) - 1) + j, j + 2 ^ (8 * i) ≤ 0, n→i(n0) ≤ i + 1, j + 2 ^ (n→i(n0) * 8 - 2) < 0, 0 ≤ 2 ^ (n→i(n0) * 8 - 1) + j, j < 0, 2 ^ (8 * i) ≤ 2 ^ (n→i(n0) * 8 - 1) ⊦ n0 = 0, n0 * 8 = 1, n0 = i→n(i) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i * j = j * i;% ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;