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Proof step 4 from proof int2bytes-len-neg (previous step)

¬ # int2bits(j) % 8 ≠ 0, j + 2 ^ (8 * i) ≤ 0, 0 ≤ 2 ^ (8 * (i + 1) - 1) + j, 0 ≤ i, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1) ⊦ # int2bytes(j) = i→n(i) + 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
# int2bits(j) % 8 = 0, 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1), 0 ≤ i, 0 ≤ 2 ^ (8 * (i + 1) - 1) + j, j + 2 ^ (8 * i) ≤ 0 ⊦ # int2bytes(j) = i→n(i) + 1

Rule argument

Additional information

Used simplifier rules: ⊦ i + j = j + i;% ⊦ i + j + i0 = (i + j) + i0;