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Proof step 40 from proof int2bytes-len-neg (previous step)

0 < i, 1 + i→n(i) * 8 < # int2bits(~1), 2 ^ (8 * i) ≤ 2 ^ (8 * (i + 1) - 1) ⊦ i = 0, # int2bits(~1) / 8 = i→n(i), # int2bits(~1) % 8 = 0

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 41:
⊦ i + 1 = 0 → int2bits(i) = true '

Rule argument

seq: ⊦ i + 1 = 0 → int2bits(i) = true ' subst: [i] → [~1] rotate: F spec: int2bits inst: name: int2bits-mone

Additional information

Used simplifier rules: ⊦ # boolvar ' = 0 +1;% ⊦ i→n(i) = 0 ↔ i = 0;% ⊦ ¬ m + n < m;% ⊦ (m + n0) + n1 = m + n0 + n1;% ⊦ m + n = n + m; Used terms: ~1