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Proof step 56 from proof int2bytes-len-neg (previous step)

0 ≤ 8 * i, m * 8 + n ≤ 8 + 8 * i→n(i), j < 0, 1 + i→n(i) * 8 < m * 8 + n, 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 2 ^ (n→i(m) * 8 + n→i(n) - 1), j + 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 0, 0 ≤ 2 ^ (n→i(m) * 8 + n→i(n) - 1) + j, n < 8, j < ~1, 8 * i ≤ 8 * (i + 1) - 1, 0 ≤ i ⊦ ~1 = i, j + 2 ^ (8 * i) = 0, m = i→n(i), n = 0, 8 * (i + 1) = 1, m = 0 ∧ n = 1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 57:
m * 8 + n ≤ 8 + 8 * i→n(i), j < 0, 1 + i→n(i) * 8 < m * 8 + n, 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 2 ^ (n→i(m) * 8 + n→i(n) - 1), j + 2 ^ (n→i(m) * 8 + n→i(n) - 2) < 0, 0 ≤ 2 ^ (n→i(m) * 8 + n→i(n) - 1) + j, n < 8, j < ~1, 0 ≤ i ⊦ ~1 = i, j + 2 ^ (8 * i) = 0, m = i→n(i), n = 0, 8 * (i + 1) = 1, m = 0 ∧ n = 1

Rule argument

Additional information

Used simplifier rules: ⊦ i + j + i0 = (i + j) + i0;% ⊦ i ≤ i;% ⊦ i < j + 1 ↔ i ≤ j;% ⊦ 0 < i → (i * j < i * j0 ↔ j < j0);% ⊦ i + 1 ≤ j ↔ i < j;% ⊦ i ≤ j - i0 ↔ i + i0 ≤ j;% ⊦ i + j = j + i;% ⊦ m * n = n * m;% ⊦ i * j = j * i;% ⊦ i * j * j0 = (i * j) * j0;% ⊦ i ≤ 0 ∧ 0 ≤ j → i ≤ j;% ⊦ 0 < i → (0 ≤ i * j ↔ 0 ≤ j);