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Proof step 1 from proof int2bytes-len-one-01 (conclusion)

⊦ # int2bytes(i) = 1 ↔ int2bytes(i) = i2b(i) '

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
⊦ # int2bytes(i) = 1 ↔ i = b2i(i2b(i))

Rule argument

Additional information

Used simplifier rules: int2bytes-len-one: ⊦ int2bytes(i) = by ' ↔ i = b2i(by);