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Proof step 16 from proof int2bytes-len-one-01 (previous step)

i = b2i(i2b(i)) ⊦ # int2bytes(i) = 1

User applied rule insert equation

And closed the goal!

Rule argument

pos: left 1 flags: discard

Additional information

Used simplifier rules: int2bytes-byte-01: ⊦ int2bytes(b2i(by)) = by ';% ⊦ # by ' = 0 +1;