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Proof step 3 from proof int2bytes-len-one-01 (previous step)

# int2bytes(i) = 1 ⊦ i = b2i(i2b(i))

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i
Proof step 5:
¬(~128 ≤ i ∧ i ≤ 127), # int2bytes(i) = 1 ⊦ i = b2i(i2b(i))

Rule argument

seq: ⊦ ~128 ≤ i ∧ i ≤ 127 → b2i(i2b(i)) = i subst: [i] → [i] rotate: F spec: byte inst: name: bib-in-01

Additional information

Used terms: i